Posted by **Farah** on Saturday, December 4, 2010 at 3:00am.

A sharpshooter shoots the bullet horizontally over level ground with a velocity of 300m/s. At the instant that the bullet leaves the barrel, its empty shell casing falls vertically and strikes the ground with a vertical velocity of 5m/s.

How far does the bullet travel?

- Physics - Dynamics in two dimensions -
**Farah**, Saturday, December 4, 2010 at 5:11am
is 153m the correct answer?

- Physics - Dynamics in two dimensions -
**drwls**, Saturday, December 4, 2010 at 7:01am
The fall time of the bullet is

t = (5 m/s)/g = 0.510 s

If you assume the bullet does not slow down, it travels 300 m/s * 0.510 s = 153 m

So you are correct.

The bullet actually will slow down somewhat due to aerodynamic drag, but neglecting the drag on bullets is not a bad assumption.

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