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July 30, 2014

July 30, 2014

Posted by **Anonymous** on Saturday, December 4, 2010 at 2:07am.

- physics -
**drwls**, Saturday, December 4, 2010 at 2:22amAdd the two vectors.

Net displacement west is 145 + 65 cos45

Net displacement south is 65 sin45

- physics -
**Anonymous**, Saturday, December 4, 2010 at 2:38amThat did not work...

- physics -
**drwls**, Saturday, December 4, 2010 at 6:05amYou must not have done the vector addition correctly. If you show your work, the error can probably be found.

You will need to use the Pythagorean relation for the magnitude.

The sin and cos of 45 degrees are both 0.707

- physics -
**Anonymous**, Saturday, December 4, 2010 at 5:18pmA car is driven 115 km west and then 85 km southwest. What is the displacement of the car from the point of origin (magnitude and direction)?

- physics -
**Anonymous**, Saturday, December 4, 2010 at 5:19pmA car is driven 115 km west and then 85 km southwest. What is the displacement of the car from the point of origin (magnitude and direction)?

- physics -
**neeza**, Sunday, February 27, 2011 at 10:26ama car travels 80 km due north and then 140 km in the direction west of north. find the magnitude and direction of the cars resultant displacementby drawing an accurate scale diagram.

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