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March 6, 2015

March 6, 2015

Posted by **Chelsea** on Friday, December 3, 2010 at 11:35pm.

- Physics -
**drwls**, Saturday, December 4, 2010 at 1:29amIf the plant efficiency is 31%, 69% of the nuclear reaction heat is carried away in cooling water. That would be (.69/.31)*1200 MW or 2670*10^6 Watts.

Transferring that heat to water flowing at 10^6 kg/s will raise the temperature by an amount deltaT, such that

2670*10^6 W = dM/dt*C*(deltaT)

deltaT = (2670*10^6 J/s)/(10^6 kg/s*4184 J/kg*C)= 0.64 C

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