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March 26, 2017

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A compound is composed of 19.998% carbon, 3.331% hydrogen, 23.320% nitrogen, and 53.302% Oxygen. Its molar ass is 120.07 gram/mole. What are the empirical and molecular formulas?

  • chemistry - ,

    There is a good rote way to do these:

    19.998% carbon, 3.331% hydrogen, 23.320% nitrogen, and 53.302% oxygen

    Assume 100 g

    19.998g carbon, 3.331g hydrogen, 23.320g nitrogen, and 53.302g oxygen

    divide by molar mass of each

    19.998/12 carbon, 3.331/1 hydrogen, 23.320/14 nitrogen, and 53.302/16 oxygen

    1.667 mole carbon, 3.331 mole hydrogen, 1.667 mole nitrogen, and 3.331 mole oxygen

    divide by smallest to get ratio

    1 mole carbon, 2 mole hydrogen, 1 mole nitrogen, and 2 mole oxygen

    so empirical is

    CH2NO2

    molar mass of which is 60 g mole^-1

    so molecular formula is

    C2H4N2O4

    1,1-dinitroethane ???

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