show that the mass number and the number of protons are conserved in the following nuclear equation:
234 230 4
92 U-----> 90 th + 2 he
I am not following protocol, I know, but this makes it MUCH easier to read. I will type the atomic number BEFORE the symbol and the mass number AFTER the symbol and as a superscript.
92U^234 --> 90Th^230 + 2He^4
The subscripts must add to the same on both sides and the superscripts must add to the same on both sides.
Note 92 protons on the left = 90+2 = 92 protons on the right.
Note 234 nucleons (protons + neutrons or mass number) on the left adds to 230 + 4 = 234 on the right.
So protons and neutrons are equal are conserved.
Sure, let's break it down step by step:
In the original uranium (U) atom, we have:
- Mass number: 234
- Number of protons: 92
In the thorium (Th) atom produced, we have:
- Mass number: 230
- Number of protons: 90
In the helium (He) atom produced, we have:
- Mass number: 4 (since it's written as 2 underneath the element symbol, we know its mass number is 4)
- Number of protons: 2
Now, let's check if the mass number and the number of protons are conserved:
For the mass number:
234 = 230 + 4
And for the number of protons:
92 = 90 + 2
So, voila! The mass number and the number of protons are conserved in this nuclear equation. Don't worry, no protons went missing or took a vacation without telling their friends!
To show that the mass number and the number of protons are conserved in the given nuclear equation, we need to calculate the mass numbers and the number of protons on both sides of the equation.
On the left side of the equation, we have uranium-234 (U-234), which has a mass number of 234 and a proton number (atomic number) of 92.
On the right side of the equation, we have thorium-230 (Th-230) and helium-2 (He-2). Thorium-230 has a mass number of 230 and a proton number of 90, while helium-2 has a mass number of 2 and a proton number of 2.
Now, let's check if the mass numbers and the number of protons are conserved:
Mass Number Conservation:
On the left side, the mass number of uranium-234 (234) is equal to the mass number of thorium-230 (230) plus the mass number of helium-2 (2). This shows that mass number is conserved: 234 = 230 + 2.
Number of Protons Conservation:
On the left side, the number of protons of uranium-234 (92) is equal to the number of protons of thorium-230 (90) plus the number of protons of helium-2 (2). This shows that the number of protons is conserved: 92 = 90 + 2.
Therefore, we have shown that the mass number and the number of protons are conserved in the given nuclear equation.
To show that the mass number and the number of protons are conserved in a nuclear equation, we need to compare the sum of the mass numbers and the sum of the number of protons on both sides of the equation.
Let's break down the nuclear equation provided:
235 231 4
92 U -----> 90 th + 2 he
The numbers on the top left of the chemical symbols are the mass numbers, and the numbers on the bottom left are the atomic numbers (number of protons).
On the left side of the equation:
Mass number = 235
Number of protons = 92
On the right side of the equation:
Mass number = 231 + 4 = 235
Number of protons = 90 + 2 = 92
As you can see, the sum of the mass numbers and the number of protons on both sides of the equation is the same. Therefore, the mass number and the number of protons are conserved in this nuclear equation.