Posted by **Eden** on Thursday, December 2, 2010 at 9:17pm.

A 0.70 kg mass at the end of a spring vibrates 4.0 times per second with an amplitude of 0.15 m.

Determine the velocity when it passes the equilibrium point.

Determine the velocity when it is 0.11 from equilibrium.

Determine the total energy of the system.

- Physics -
**Eden**, Thursday, December 2, 2010 at 9:18pm
sorry, .11 m from equilibrium.

- Physics -
**bobpursley**, Thursday, December 2, 2010 at 9:29pm
start with the basic equations.

x=A*sinwt

v= Aw*coswt

a= -Aw^2sinwt

at the equilibrium point wt is PI (cosine is max), so V-Aw you know A, and w=2PI/Period, and period is given (.25sec).

when position is .11,

.11=Asinwt solve for wt, then v= Awcoswt

energy? 1/2 m v^2 where v is vmax, or Aw

- Physics -
**Eden**, Thursday, December 2, 2010 at 9:51pm
what is Pl?

- Physics -
**bobpursley**, Thursday, December 2, 2010 at 9:53pm
PI is 3.14159...

- Physics -
**Eden**, Thursday, December 2, 2010 at 9:54pm
oh... pi... thanks

- Physics -
**Anonymous**, Sunday, October 7, 2012 at 8:40pm
how do you know period is .25 sec?

- Physics -
**Anonymous**, Wednesday, January 2, 2013 at 10:30pm
frequency is four times per second! (1 sec divided by four times is .25)

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