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March 27, 2015

March 27, 2015

Posted by **Rebecca** on Thursday, December 2, 2010 at 8:25pm.

y = sq. root [(x^2 - 1)/(x^2 + 1)]

- Calc -
**MathMate**, Thursday, December 2, 2010 at 10:06pmy = sq. root [(x^2 - 1)/(x^2 + 1)]

take log (to base e, =ln) on both sides

log(y) = (1/2)(log(x²-1)-log(x²+1)

differentiate with respect to x

dy/dx / y = x/(x²-1)-x/(x²+1)

= 2x/((x²-1)(x²+1))

dy/dx = x/(x²-1)-x/(x²+1)

= 2x/((x²-1)(x²+1)) * √(x²-1)/√(x²+1)

Simplify.

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