Ceramic tiles measure 2 inches by 3 inches. What is the least number of tiles that are needed to completely cover a square area that is 2 feet on each side?
Let x = # tiles
144 in^2 = 1 ft^2
2ft * 2ft = 4ft^2
4ft^2 = 6/144ft^2 * x
Solve for x.
To find the least number of ceramic tiles needed to completely cover a square area that is 2 feet on each side, we need to convert the measurements to a consistent unit.
Given that ceramic tiles measure 2 inches by 3 inches, we can convert the side length of the square area to inches.
1 foot is equal to 12 inches, so the square area measures 2 feet * 12 inches per foot = 24 inches on each side.
Now, we can determine how many tiles fit along the length and width.
For the length of the square area, we have 24 inches / 2 inches per tile = 12 tiles.
For the width of the square area, we have 24 inches / 3 inches per tile = 8 tiles.
Finally, to find the total number of tiles needed, we multiply the number of tiles along the length by the number of tiles along the width:
12 tiles * 8 tiles = 96 tiles.
Hence, the least number of tiles needed to completely cover a square area that is 2 feet on each side is 96 tiles.