Write a balanced chemical equation for the reaction for propane C3H8 burning in oxygen to for carbon dioxide and water vapor
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To write a balanced chemical equation for the combustion of propane (C3H8) in oxygen (O2) to form carbon dioxide (CO2) and water vapor (H2O), you need to follow these steps:
Step 1: Write the formula for propane and oxygen.
Propane: C3H8
Oxygen: O2
Step 2: Write the products formed after combustion.
Carbon dioxide: CO2
Water vapor: H2O
Step 3: Set up the unbalanced equation.
C3H8 + O2 -> CO2 + H2O
Step 4: Balance the equation.
Start by balancing the carbon atoms:
C3H8 + O2 -> 3CO2 + H2O
Next, balance the hydrogen atoms:
C3H8 + O2 -> 3CO2 + 4H2O
Finally, balance the oxygen atoms:
C3H8 + 5O2 -> 3CO2 + 4H2O
Therefore, the balanced chemical equation for the combustion of propane in oxygen to form carbon dioxide and water vapor is:
C3H8 + 5O2 -> 3CO2 + 4H2O
The balanced chemical equation for the combustion of propane (C3H8) in oxygen (O2) to form carbon dioxide (CO2) and water vapor (H2O) can be written as follows:
C3H8 + 5O2 -> 3CO2 + 4H2O
This equation indicates that one molecule of propane reacts with five molecules of oxygen to produce three molecules of carbon dioxide and four molecules of water.