Posted by Anonymous on .
one number is two less than a second number. If you take onehalf of the first number and increase it by the second number,the result is atleast 41. find the least possible value for the second number.

algebra 2 
Reiny,
second number  x
first number  x2
"If you take onehalf of the first number and increase it by the second number,the result is atleast 41"
> (1/2)x + x2 ≥ 41
solve for x to get your second number, then evaluate x2 for the first.
It is up to you to decide if only whole numbers are allowed or if you include fractions.