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December 18, 2014

December 18, 2014

Posted by **Adam** on Wednesday, December 1, 2010 at 11:21pm.

int f(x,y) dydx

where y bounds= 1 to e^x and x bounds= 0 to 4

I thought the new bounds were

int f(x,y) dxdy

x= 0 to log(y) y= 1 to e^4

Please let me know if I'm on the right track thank you:)

- CALC -
**MathMate**, Thursday, December 2, 2010 at 12:08amIf you are finding the area bounded by y=1, y=54.6(approx), x=0, x=4, and f(x,y)=e^x, or any other one-to-one function, and if the limits for

∫e^x dydx

are y=1,f(x,y), x=0,4

then

changing the order could be:

x=e^x to 4, y=1, e^4.

However, it depends on the properties of the function, is it one-to-one, is it invertible, etc.

plot for e^x within the integration limits:

http://img829.imageshack.us/img829/1476/1291263700.png

- CALC -
**Adam**, Thursday, December 2, 2010 at 12:23amOh I see thank you

but the new bounds after you have changed the order shouldn't it be

x= log(y)to 4 --> because I rearranged the bounds from y=e^x to x=log(y)?

- CALC -
**MathMate**, Thursday, December 2, 2010 at 6:51amYes, indeed. Don't understand why I didn't see it in the first place.

- CALC -
**Adam**, Friday, December 3, 2010 at 1:15amAwesome thank you :)

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