Posted by tom on Wednesday, December 1, 2010 at 8:10pm.
A 3.2 kg block is hanging stationary from the end of a vertical spring that is attached to the ceiling. The elastic potential energy of this spring/mass sytem is 2.1 J. What is the elastic potential energy of the system when the 3.2 kg block is replaced by a 5.3 kg block?

honors physics  bobpursley, Wednesday, December 1, 2010 at 8:13pm
find k for the initial block.
Weight= kx when
2.1J=1/2 kx^2 or
mg=kx and
4.2J=kx^2 or
4.2=mg*x solve for x
know, knowing x, solve for k.
replace the mass, find new x.
PE= 1/2 k (newx)^2
Answer This Question
Related Questions
 Physics  A 3.2 kg block is hanging stationary from the end of a vertical spring...
 physics  A 2.8kg block is hanging stationary from the end of a vertical spring...
 college  A 3.2 kg block is hanging stationary from the end of a vertical spring...
 Physics Help!!!! Please check  We had worked this one out before but due to my ...
 Physics Urgent  A 3.2 kg block is hanging stationary from the end of a vertical...
 Physics ( elestic potential energy)  A spring with a force of 5.2 N/m has a ...
 physics  A 2.40 kg object is hanging from the end of a vertical spring. The ...
 help on physics  A 3.30 kg object is hanging from the end of a vertical spring...
 Physics  A block with mass m = 2.00 kg is placed against a spring on a ...
 physics  a spring with spring constant k= 100N/m is at its equilibrium length a...
More Related Questions