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April 16, 2014

April 16, 2014

Posted by **Jimmy Larson** on Wednesday, December 1, 2010 at 5:22pm.

- Calculas -
**bobpursley**, Wednesday, December 1, 2010 at 5:25pmlet x be the horizontal distance to the dock.

x^2=R^2-100 where R is rope length to the pulley.

2x dx/dt=2RdR/dT

solve for dx/dt when R is 125? (x= sqrt(125^2-100). dR/dt= 20ft/min

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