3x^2+11x+5=15?
3x^2+11x+5=15
3x^2+11x+5-15=0
3x^2+11x-10=0
ax^2+bx+c=0
a=3 , b=11 , c=-10
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3x^2 + 11x - 10 = 0
Factor.
(3x-5)(x-2) = 0
3x-5 = 0
x = 5/3
x-2 = 0
x = 2
5X2-(-2)
To solve the equation 3x^2 + 11x + 5 = 15, we want to isolate the variable x. Here's a step-by-step explanation of how to solve this:
Step 1: Subtract 15 from both sides of the equation to get 3x^2 + 11x + 5 - 15 = 0. Simplify the equation to get 3x^2 + 11x - 10 = 0.
Step 2: Now, we need to factor the quadratic equation 3x^2 + 11x - 10 = 0. To do this, we look for two numbers that multiply to give -10 and add up to 11. These numbers are 10 and -1. So, the equation can be factored as (3x - 1)(x + 10) = 0.
Step 3: Set each factor equal to zero. So, we have 3x - 1 = 0 or x + 10 = 0.
Step 4: Solve for x in each equation separately.
- For 3x - 1 = 0, we add 1 to both sides of the equation to get 3x = 1. Then, we divide both sides by 3 to get x = 1/3.
- For x + 10 = 0, we subtract 10 from both sides of the equation to get x = -10.
Step 5: The solutions to the equation 3x^2 + 11x + 5 = 15 are x = 1/3 and x = -10.