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April 1, 2015

April 1, 2015

Posted by **sara** on Wednesday, December 1, 2010 at 12:47pm.

25 47 32 56

At a .05 level of significance, determine whether or not the mean of the population from which this sample was taken is significantly different from 48. (Assume the population is normally distributed.)

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**PsyDAG**, Thursday, December 2, 2010 at 4:08pmZ = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.

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