A sample of 0.0020 mole of HCl is sissolved in water t omake a 2000ml solution. Calculate the molarity of the HCl solution, the (H30+) and the pH. For a strong acide such as HCl the (h30+) is the same as the molarity of the HCl solution.
HCl +H20 Balanced equation H30+ +Cl
To calculate the molarity of the HCl solution, we need to use the formula:
Molarity (M) = Number of moles (n) / Volume of solution (V)
Given that the sample contains 0.0020 mole of HCl and the solution is 2000 mL (or 2.000 L), we can substitute these values into the formula:
Molarity (M) = 0.0020 mole / 2.000 L
Molarity (M) = 0.001 M
Therefore, the molarity of the HCl solution is 0.001 M.
Since HCl is a strong acid, the concentration of (H3O+) ions is the same as the molarity of the HCl solution. Therefore, the (H3O+) concentration is also 0.001 M.
To calculate the pH, we use the formula:
pH = -log(H3O+)
Substituting the (H3O+) concentration into the formula:
pH = -log(0.001)
pH = -(-3)
pH = 3
Therefore, the pH of the HCl solution is 3.