How to solve the simultaneous equations 3x + y = 17 and y = x + 1 ?

There are a few ways to do this. In this case the easiest is probably substituting y in the first equation for x+1

so

3x + (x + 1) =17

remove the brackets

3x + x + 1 = 17

combine the x terms

4x + 1 = 17

move the 1 from the LHS to the RHS

4x +1 -1 = 17 - 1

4x = 16

divide both sides by 4

4x/4 = 16/4

x=4

as

y=x+1

y= 4 + 1

y=5

To solve the simultaneous equations 3x + y = 17 and y = x + 1, you can use the method of substitution or the method of elimination. Let's go through both methods:

Method 1: Substitution

Step 1: Solve one equation for one variable.
We have the equation y = x + 1. Let's solve it for y.
Rearranging the equation, we have x = y - 1.

Step 2: Substitute the expression into the other equation.
Now, substitute the expression for x (from Step 1) into the other equation (3x + y = 17).
Replace x with y - 1, giving us:
3(y - 1) + y = 17

Step 3: Simplify and solve for y.
Distribute the 3:
3y - 3 + y = 17
Combine like terms:
4y - 3 = 17
Add 3 to both sides:
4y = 20
Divide by 4:
y = 5

Step 4: Substitute the value of y back into either of the original equations and solve for x.
Using y = 5, substitute it into y = x + 1:
5 = x + 1
Subtract 1 from both sides:
x = 4

Therefore, the solution to the simultaneous equations 3x + y = 17 and y = x + 1 is x = 4 and y = 5.

Method 2: Elimination

Step 1: Multiply one or both equations by suitable numbers to make the coefficients of one variable the same or multiples of each other.
Both equations are already in a form where the coefficients of y are the same, so we can directly proceed to the next step.

Step 2: Add or subtract the equations to eliminate one of the variables.
Since the coefficients of y in both equations are 1, we can simply subtract the equations.
(3x + y) - (y) = (17) - (x + 1)
3x - x = 17 - 1
2x = 16
Divide by 2:
x = 8

Step 3: Substitute the value of x back into either of the original equations and solve for y.
Using x = 8, substitute it into 3x + y = 17:
3(8) + y = 17
24 + y = 17
Subtract 24 from both sides:
y = 17 - 24
y = -7

Therefore, the solution to the simultaneous equations 3x + y = 17 and y = x + 1 is x = 8 and y = -7.

Both methods should give you the same solution, which is x = 4 and y = 5.