Posted by **Laura Hieb** on Wednesday, December 1, 2010 at 1:07am.

Only 27% of the carbon-14 in a wooden bowl remains. How old is the bowl? (Carbon-14 has a half-life of 5,700 years.)

- College Algebra -
**drwls**, Wednesday, December 1, 2010 at 3:43am
Let T be the age in years.

0.27 = (0.5)^(T/5700)

Take logs of both sides to solve.

T/5700 = log(0.27)/log(0.5) = 1.889

T = ___ years

- College Algebra -
**josh**, Wednesday, December 1, 2010 at 10:42pm
65437990

- College Algebra -
**lia mowin**, Thursday, December 2, 2010 at 1:00am
well the bowel has 27% carbon-14 remaining which means that 73% of the carbon-14 has already been depleted. 5700 years is the half life of carbon-14 so to get the full life we multiply 5700(2)=11400 years. then we can do an easy cross multiplication problem to figure it out, x/11400=73/100 and then we solve for x which is x=11400(73)/100 and the final answer and age of the bowel is 8322 years. a very algebraic way of solving it lol

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