Posted by Dana on Wednesday, December 1, 2010 at 12:50am.
The closest point?
let a be the distance, so 14-a is the other distance.
Now to be zero amplitude, these two waves have to be 1/2 Lambda different.
Lambda= 340m/1020=.333m
lambda/2= .167m
well, (14-a)/.167-.5=a/.167
14-a-.0833=a
a=6.958m
checking this (I dont believe it)
6.958/.167=41.66 half wavelengths
(14-6.958)/.167=42.17 half wavelengths
the difference is indeed half wavelength.
check my work, I am still wondering.
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