what is the pH of an 0.155M aqueous solution of acetic acid if the Ka is 1.8 EE -5?
CH3COOH ==> H^+ + H3COO^-
Ka = (H^+)(CH3COO^-)/(CH3COOH)
(H^+) = x
(CH3COO^-) = x
(CH3COOH) = 0.155-x
Solve for x and convert to pH.
Ka = (H^+)(CH3COO^-)/(CH3COOH)
(H^+) = x
(CH3COO^-) = x
(CH3COOH) = 0.155-x
Solve for x and convert to pH.