What is the maximum [Ba^2+] that can be maintained in 1.100 L of a 030 M solution of Na2SO4?
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BaSO4 ==> ba^+2 + SO4^-2
Ksp = (Ba^+2)(SO4^-2)
You know Ksp, substitute 0.30 M for SO4^-2 and solve for Ba^+2. That will give you moles/L and that concn will not change for different volumes. That means that concn Ba^+, in M, will be the same in 100 mL or 15 L. That's the way I've interpreted your statement. If you want to know moles, then use the molarity you calculated above and multiply by 1.1.
To determine the maximum concentration of Ba^2+ ions that can be maintained in the given solution, we need to consider the solubility product constant (Ksp) for barium sulfate (BaSO4) and the stoichiometry of the chemical reaction.
The solubility product constant (Ksp) for BaSO4 is given by the expression:
BaSO4 ⇌ Ba^2+ + SO4^2-
Ksp = [Ba^2+] * [SO4^2-]
The balanced chemical equation for the dissociation of BaSO4 shows that one mole of BaSO4 dissociates to produce one mole of Ba^2+ and one mole of SO4^2-.
Therefore, the stoichiometry of the reaction indicates that the concentration of Ba^2+ ions in the solution is equal to the concentration of BaSO4.
Given:
Volume of the solution (V) = 1.100 L
Initial concentration of Na2SO4 (C) = 0.030 M
To find the maximum concentration of Ba^2+, we need to calculate the maximum number of moles of BaSO4 that can dissolve in the given volume of solution and then convert it to concentration.
Step 1: Calculate the moles of Na2SO4 in the solution:
Moles of Na2SO4 = Concentration (C) * Volume (V)
Moles of Na2SO4 = 0.030 M * 1.100 L
Step 2: Find the molar ratio between BaSO4 and Na2SO4:
From the balanced chemical equation, we know that one mole of BaSO4 reacts with one mole of Na2SO4. Therefore, the molar ratio is 1:1.
Step 3: Calculate the maximum moles of BaSO4:
Moles of BaSO4 = Moles of Na2SO4
Step 4: Convert moles of BaSO4 to concentration of Ba^2+:
Concentration of Ba^2+ = Moles of BaSO4 / Volume (V)
Now you can follow the steps mentioned above, substitute the values, and calculate the maximum concentration of Ba^2+ in the given solution of Na2SO4.