Posted by **Kelsey G** on Tuesday, November 30, 2010 at 7:31pm.

Determine the volume of 0.250 M KOH solution required to neutralize each of the following samples of sulfuric acid. The neutralization reaction is:

H2SO4(aq) + 2KOH(aq) = K2SO49aq) + 2H2O(l)

Find: 15 mL of 0.250 M H2SO4

## Answer this Question

## Related Questions

- Chemistry - Determine the volume of 0.250 M KOH solution required to neutralize ...
- chem - Determine the volume of 0.240 M KOH solution required to neutralize each ...
- Chemistry - Determine the volume of 0.240 M KOH solution required to neutralize ...
- Chemistry (repost) - Determine the volume of 0.240 M KOH solution required to ...
- Chemistry - A volume of 80.0mL of aqueous potassium hydroxide (KOH) was titrated...
- chemistry 112 - A volume of 60.0mL of aqueous potassium hydroxide (KOH) was ...
- pcc - A volume of 40.0mL of aqueous potassium hydroxide (KOH) was titrated ...
- Chemistry - A volume of 40.0 of aqueous potassium hydroxide (KOH) was titrated ...
- Chem - Determine the volume of 0.250M KOH solution required to neutralize each ...
- Chemistry - A volume of 60.0 of aqueous potassium hydroxide (KOH) was titrated ...

More Related Questions