if C6H12O6 -> 2 C2H5OH + 2 CO2 represents the fermentation of sugar to produce alcohol, and the reaction is only 40.0% efficient (% yield), what is the actual yield of alcohol from 454 g of C6H12O6
Another stoichiometry problem but with a slight hitch at the end. Here is a solved example of a stoichiometry problem. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
After you have gone through the example, you will have arrived at the theoretical yield. Just multiply that by 0.400 to arrive at the actual yield.
To find the actual yield of alcohol from 454 g of C6H12O6, we first need to calculate the theoretical yield of alcohol using the given balanced equation.
According to the balanced equation, 1 mole of C6H12O6 produces 2 moles of C2H5OH. Therefore, we need to convert the mass of C6H12O6 to moles, and then use the mole ratio to determine the moles of C2H5OH produced.
Step 1: Calculate the number of moles of C6H12O6.
To do this, we need to know the molar mass of C6H12O6.
C6H12O6 = (6*12.01 g/mol) + (12*1.01 g/mol) + (6*16.00 g/mol) = 180.18 g/mol.
Moles of C6H12O6 = mass (g) / molar mass (g/mol)
Moles of C6H12O6 = 454 g / 180.18 g/mol
Moles of C6H12O6 ≈ 2.52 mol
Step 2: Determine the moles of C2H5OH produced.
From the balanced equation, we know that 1 mole of C6H12O6 produces 2 moles of C2H5OH.
Moles of C2H5OH = Moles of C6H12O6 * (2 moles of C2H5OH / 1 mole of C6H12O6)
Moles of C2H5OH ≈ 2.52 mol * (2/1)
Moles of C2H5OH ≈ 5.04 mol
Step 3: Calculate the actual yield of alcohol.
The yield given is 40.0%, which means that only 40.0% of the theoretical yield is obtained. To find the actual yield of alcohol, we multiply the theoretical yield by the yield percentage.
Actual yield of alcohol = Theoretical yield of alcohol * (% yield / 100)
Actual yield of alcohol = 5.04 mol * (40.0/100)
Actual yield of alcohol ≈ 2.02 mol
Finally, if we assume the molar mass of C2H5OH is approximately 46.08 g/mol, we can calculate the actual yield in grams:
Actual yield of alcohol = moles of alcohol * molar mass of alcohol
Actual yield of alcohol ≈ 2.02 mol * 46.08 g/mol
Actual yield of alcohol ≈ 93.22 g
Therefore, the actual yield of alcohol from 454 g of C6H12O6 is approximately 93.22 grams.