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An air puck of mass m1 = 0.45 kg is tied to a string and allowed to revolve in a circle of radius R = 1.0 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass m2 = 1.10 kg is attached to it. The suspended mass remains in equilibrium while the puck on the tables revolves.
A) What is the tension T in the string?
B) What is the magnitude of the horizontal force acting on the air puck?
C) What is the speed of the puck

  • physics -

    Teresa's class?

  • physics -

    sorry =[

  • physics -

    a)What is the tension T in the string?

    in this case, tension = mass2 X gravity
    so, tension = 1.10 kg X 9.8 m/s^2
    tension = 10.78

    For letter b, I am afraid I have no clue :(

    c)What is the speed of the puck?

    F = (m(v^2))/r

    the tension is the force in this case, so:

    tension = (m1(v^2))/r

    v^2 = (tension X r)/m1

    v^2 = (10.78 N X 1.0 m)/ .45 kg

    v^2 = 23.95555556 m/s
    Take the square root of both sides
    v = 4.894441291 m/s

  • physics -

    part a is the same as part b ;)

  • physics -

    For B, the magnitude is simply the absolute value of what you got in part A.

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