Posted by melissa on .
An air puck of mass m1 = 0.45 kg is tied to a string and allowed to revolve in a circle of radius R = 1.0 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass m2 = 1.10 kg is attached to it. The suspended mass remains in equilibrium while the puck on the tables revolves.
A) What is the tension T in the string?
B) What is the magnitude of the horizontal force acting on the air puck?
C) What is the speed of the puck

physics 
Anonymous,
Teresa's class?

physics 
Anonymous,
sorry =[

physics 
Brianna,
a)What is the tension T in the string?
in this case, tension = mass2 X gravity
so, tension = 1.10 kg X 9.8 m/s^2
tension = 10.78
For letter b, I am afraid I have no clue :(
c)What is the speed of the puck?
F = (m(v^2))/r
the tension is the force in this case, so:
tension = (m1(v^2))/r
v^2 = (tension X r)/m1
v^2 = (10.78 N X 1.0 m)/ .45 kg
v^2 = 23.95555556 m/s
Take the square root of both sides
v = 4.894441291 m/s 
physics 
Jake Conner,
part a is the same as part b ;)

physics 
Lisa,
For B, the magnitude is simply the absolute value of what you got in part A.