Posted by **Y0gi** on Tuesday, November 30, 2010 at 11:05am.

60) A class of 10 students taking an exam has a power output per student of about 200W. Assume the initial temperature of the room is 20 C and that its dimensions are 6.0 m by 15.0 m by 3.0 m. What is the temperature of the room at the end of 1.0 h if all the energy remains in the air in the room and none is added by an outside source? The specific heat is 837 J/kg C, and its density is about 1.3 x 10^-3 g/cm^3

I just need the work shown

The answer is 44.5 C (= 112 F)

- Physics -
**drwls**, Tuesday, November 30, 2010 at 11:13am
The heat generated by the students at the end of one hour is

10*(200 J/s)*3600 s = ___ Joules

Divide that by the heat capacity of the air in the room,

(Volume)*(air density)*Specific heat)

The ratio will be the temperature rise.

The high value is the result of erroneous assumptions. In a real case, most of the added heat would be lost to the walls and objects in the room.

You do the calculations

- Physics -
**Y0gi**, Tuesday, November 30, 2010 at 12:24pm
I did as you said. The only thing I did not see you add to the equation though is the initial temperature of the room. I don't know if I did it right because after your instructions I just added that 20 C to the final answer and it gave me 44.5! I don't know if it's right but it gave me the correct answer.

## Answer this Question

## Related Questions

- Physics - A class of 11 students taking an exam has a power output per student ...
- physics - A class of 11 students taking an exam has a power output per student ...
- Physics - A class of 11 students taking an exam has a power output per student ...
- statistics and probability - It is known that an exam scores of students in STAT...
- Unit 1 - Math please in a certain school 55 students are taking French this ...
- JAVA PROGRAMMING - im new to java and this is my first assignment can anyone ...
- Teacher approach - When I entered the art room, the students were painting but ...
- Math - First period: 85, 83, 74, 70, 88,95,89,72,90,83,77,91,98,89,82,84 Second ...
- Statistics help? - Hi there, I was looking for any assistance or help on how I ...
- Statistics on Psychology - Hi there, I was looking for any assistance or help on...

More Related Questions