Posted by Y0gi on Tuesday, November 30, 2010 at 11:05am.
The heat generated by the students at the end of one hour is
10*(200 J/s)*3600 s = ___ Joules
Divide that by the heat capacity of the air in the room,
(Volume)*(air density)*Specific heat)
The ratio will be the temperature rise.
The high value is the result of erroneous assumptions. In a real case, most of the added heat would be lost to the walls and objects in the room.
You do the calculations
I did as you said. The only thing I did not see you add to the equation though is the initial temperature of the room. I don't know if I did it right because after your instructions I just added that 20 C to the final answer and it gave me 44.5! I don't know if it's right but it gave me the correct answer.
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