Posted by Kiddo on .
a 145g baseball is thrown up at 40 m/s. after traveling a distance of 50m in the air, the baseball is caught. the ball experienced air resistance of what magnitude?
Thrown straight up?
For the straight-up case, the ball must have travelled 25 m up and back down. A ball thrown at 40 m/s with no friction would have risen H = V^2/(2g) = 81.6 m
There is no way the height of a baseball thrown up in air will be reduced from 81.6 m to 25 m by friction.
This is a poorly conceived and inadequately explained question
If a baseball is thrown 30 m/s backwards from a truck moving 50 m/s, how fast will the ball strike the glove of a ground-based catcher?