A 625-kg racing car completes one lap in 14.3 s around a circular track with a radius of 50.0 m. The car moves at constant speed.
(a) What is the acceleration of the car?
Your SUBJECT is not 11th grade.
yes it is
acceleration= V^2/r
v=PI*r*2/14.3
so acceleration= PI^2*4*r/14.3 put r in.
check my algebra.
Centripetal Acceleration = v^2/r
= (circumference/time)^2/r
= (2*pi*r/t)^2)/r
= ((2*3.14*50/14.3)^2)/50
= 9.64 m/s^2
Thank you! you are correct @carey
To find the acceleration of the car, we need to use the equation for centripetal acceleration. The centripetal acceleration is given by:
a = v^2 / r
Where:
a = centripetal acceleration
v = velocity of the car
r = radius of the circular track
In this case, we are given the time it takes for the car to complete one lap, but we need to find the velocity first. To find the velocity, we can use the formula:
v = 2πr / t
Where:
v = velocity of the car
r = radius of the circular track
t = time taken to complete one lap
Given:
r = 50.0 m
t = 14.3 s
Using the formula, we can calculate the velocity:
v = 2π(50.0) / 14.3
v ≈ 219.37 m/s
Now that we have the velocity, we can substitute it into the formula for centripetal acceleration:
a = (219.37)^2 / 50.0
a ≈ 959.62 m/s^2
Therefore, the acceleration of the car is approximately 959.62 m/s^2.