Posted by **john** on Monday, November 29, 2010 at 9:01pm.

A 625-kg racing car completes one lap in 14.3 s around a circular track with a radius of 50.0 m. The car moves at constant speed.

(a) What is the acceleration of the car?

- 11th grade -- math -
**Ms. Sue**, Monday, November 29, 2010 at 9:03pm
Your SUBJECT is not 11th grade.

- 11th grade -
**john**, Monday, November 29, 2010 at 9:31pm
yes it is

- 11th grade -
**bobpursley**, Monday, November 29, 2010 at 9:42pm
acceleration= V^2/r

v=PI*r*2/14.3

so acceleration= PI^2*4*r/14.3 put r in.

check my algebra.

- 11th grade -
**Carey**, Tuesday, November 30, 2010 at 12:58am
Centripetal Acceleration = v^2/r

= (circumference/time)^2/r

= (2*pi*r/t)^2)/r

= ((2*3.14*50/14.3)^2)/50

= 9.64 m/s^2

- 12th grade -
**Amira**, Monday, May 14, 2012 at 8:51pm
Thank you! you are correct @carey

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