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Posted by on Monday, November 29, 2010 at 8:57pm.

A particle moves along the x-axis with position at time t given by x(t)=e^(-t)sin(t) for 0 is less than or equal to t which is less than or equal to 2 pi.

a) Find the time t at which the particle is farthest to the left. Justify your answer

I think you have to find the prime of this equation and then see when it is negative.

b) Find the value of the constant A for which x(t) satisfies the equation Ax"(t)+x'(t)+x(t)=0 for 0 is less than t which is less than 2 pi.

I have no idea how to even start this problem.

  • Calculus - Still Need Help! Anyone! - , Monday, November 29, 2010 at 9:13pm

    a. Find the derivative, set to zero

    dx/dt= -e^-t * sint+ e^-tcost=0

    tanT=1 check that.

    t= PI/4 or 3PI/4
    Now which will make it to the left (negative x)?

    b. d^2x/dt^2= d/dx e^-t(cost-sint)
    take that dervative.

    Then, put in the equation given
    ax" + x'+ x=0 and solve for A

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