Posted by **Jennifer** on Monday, November 29, 2010 at 8:41pm.

A diver exhales a bubble with a volume of 25 mL at a pressure of 2.4 atm and a temperature of 15 degrees C. how many gas particles are in this bubble?

- College Chem -
**DrBob222**, Monday, November 29, 2010 at 9:04pm
I would use PV = nRT and solve for n = number of moles gas. One mole contains 6.022E23 molecules.

- College Chem -
**Jennifer**, Monday, November 29, 2010 at 9:37pm
We did that and somehow got the wrong answer. can you please give me a step by step?

Thank you...

- College Chem -
**niki**, Monday, November 29, 2010 at 9:41pm
n= PV/RT

n={(2.4)x(25)}/{(.082)x(288)

-> n x 6.022x10^23 = answer

- College Chem -
**DrBob222**, Monday, November 29, 2010 at 10:00pm
niki has posted but the 25 mL must be inserted as 0.025 L

- College Chem -
**Jennifer**, Monday, November 29, 2010 at 10:52pm
Thank you,

we were doing,

n=VRT

P

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