Homework Help: Physics

Posted by Thomas on Monday, November 29, 2010 at 8:35pm.

An elevator manufacturing company is stress-testing a new elevator in an airless test shaft. The elevator is traveling at an unknown velocity when the cable snaps. The elevator falls 2.50 meters before hitting the bottom of the shaft. The elevator was in free fall for 0.900 seconds. Determine its velocity when the cable snapped. As usual, up is the positive direction.

Physics - bobpursley, Monday, November 29, 2010 at 9:04pm
The average velocity during the time is

2.50/.9=(Vf+Vi)/2

or Vf+Vi=5.56m/s

Vf=Vi+gt=Vi+8.82

Vi=Vf-8.82=-Vf+5.56

2Vf=8.82+5.56 solve for Vf
Physics - Thomas, Monday, November 29, 2010 at 9:38pm
thank you
Physics - Anonymous, Wednesday, September 28, 2011 at 8:20pm
8.82

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