The length of a rectangular jewelry box is 5 inches more than twice the width. The perimeter is 28 inches. Find the length and the width.

P = 2L + 2W

28 = 2(5 + 2W) + 2W
28 = 10 + 4W + 2W
28 = 10 + 6W
18 = 6W
3 = W

Let's assign variables to the width and length of the rectangular jewelry box.

Let's say the width is represented by 'w' inches.

According to the problem, the length is 5 inches more than twice the width, which can be represented as: length = 2w + 5.

The perimeter of a rectangle is the sum of all sides, so we can set up an equation using the given perimeter of 28 inches:

Perimeter = 2(length + width)

Substituting the values we know, we get:

28 = 2((2w + 5) + w)

Now, we can solve for 'w':

28 = 2(3w + 5)
28 = 6w + 10
18 = 6w
w = 3

Now that we have found the width, we can substitute it back into our expression for the length:

length = 2w + 5
length = 2(3) + 5
length = 6 + 5
length = 11

Therefore, the length of the rectangular jewelry box is 11 inches, and the width is 3 inches.

To solve this problem, we can start by setting up equations based on the given information.

Let's assume the width of the jewelry box is "x" inches. According to the problem, the length is 5 inches more than twice the width, so it can be expressed as "2x + 5" inches.

The formula for the perimeter of a rectangle is:
Perimeter = 2(length + width)

Given that the perimeter is 28 inches, we can now write the equation as follows:
28 = 2((2x + 5) + x)

Next, we can simplify and solve the equation to find the value of "x."

28 = 2(3x + 5)
28 = 6x + 10 (using the distributive property)
6x = 28 - 10
6x = 18
x = 18/6
x = 3

So, the width of the jewelry box is 3 inches.

To find the length, we substitute the value of the width (x = 3) into the expression for the length:
Length = 2x + 5 = 2(3) + 5 = 6 + 5 = 11

Therefore, the length of the jewelry box is 11 inches and the width is 3 inches.

l =32