Math/Statistics
posted by Dave .
The mean starting salary for graduates in the spring of 2004 was $36,280. Assume that the distribution of starting salaries follows the normal distribution with a standard deviation of $3,300. What percent of the graduates have starting salaries between $35,000 and $40,000?
a. 5225
b. .0041
c. .1251
d. None of the above

Copy and paste the question into Google and the answer is there. Looks like it will be d, but check it out yourself

Here is the math
(35,000<X<40,000)=P((35,00036,280)/3,300<(X36,280)/3,300<(40,00036,280)/3,300)=P(0.3879<Z<1.1273)
=P(Z<1.1273)P(Z<0.3879)=0.87020.3491= 0.5211