Posted by **Shayne** on Monday, November 29, 2010 at 1:15pm.

A pilot wishes to fly 450 km due south in 3 hours. A wind is blowing from the west at 50 km/hr. By means of a vector diagram, compute the proper heading and speed that the pilot must choose to achieve this objective.

- Physics -
**Henry**, Tuesday, November 30, 2010 at 8:45pm
From the origin,draw a vector on the positive x axis pointing eastward.Label

it 50 km/h.

Draw a vector on the negative y axis pointing south. Label it -150 km/h.

From the origin, draw the resultant vector between the two original vectors

and pointing southeast.

tanA = Y/X = -150/50 = -3,

A = -71.6 deg. = 288.4 deg. CCW.

R = X / cosA = 50 / cos288.4 = 158.4km / h .

288.4 - 270 = 18.4 deg East of the

intended course.

To allow for windage, the plane must head 18.4 deg west of due South:

270 - 18.4 = 25i.6 deg.CCW.

d = 3 h * 158.4 km/h = 475.2 km.

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