Posted by Shayne on Monday, November 29, 2010 at 1:15pm.
From the origin,draw a vector on the positive x axis pointing eastward.Label
it 50 km/h.
Draw a vector on the negative y axis pointing south. Label it -150 km/h.
From the origin, draw the resultant vector between the two original vectors
and pointing southeast.
tanA = Y/X = -150/50 = -3,
A = -71.6 deg. = 288.4 deg. CCW.
R = X / cosA = 50 / cos288.4 = 158.4km / h .
288.4 - 270 = 18.4 deg East of the
intended course.
To allow for windage, the plane must head 18.4 deg west of due South:
270 - 18.4 = 25i.6 deg.CCW.
d = 3 h * 158.4 km/h = 475.2 km.
Related Questions
Physics - A pilot wishes to fly to a point 450 km due south in 3 hours. A windis...
Physics - Kyle wishes to fly to a point 450 km due south in 3 hours. A wind is ...
physics - The pilot of an aircraft wishes to fly due west in a 42.7 km/h wind ...
physics - The pilot of an aircraft wishes to fly due west in a 46.8 km/h wind ...
physics - An airplane pilot wishes to fly due west. A wind of 82.0 km/h is ...
Physics - An airliner is at point A and is trying to fly to point B, which is ...
physics - An airplane pilot wishes to fly due west. A wind of 82.0m/s is blowing...
physics - You are a pilot on an aircraft carrier. You must fly to another ...
physics URGENT! PLEASE - Figure the resultant velocity of a plane that is ...
Physics - The pilot of an aircraft wishes to fly due west in a 52.6 km...
For Further Reading
