Posted by Michelle on Monday, November 29, 2010 at 12:29pm.
2AgNO3 + CaCl2 ==> 2AgCl + Ca(NO3)2
mole AgCl = 110.5/molar mass = ??
moles CaCl2 used = moles AgCl x (1 mole CaCl2/2 moles AgCl) = ??
M CaCl2 = moles CaCl2/L CaCl2.
Solve for L CaCl2 and convert to mL.
All of this depends, of course, upon the reaction being complete and recovery being 100% of the theoretical yield.
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