Thanks you alot for correction. A car is travelling with a 5m/s in 25 minutes at a distance of 30 cm calculate initial velocity and decelaration of the car.

To calculate the initial velocity and deceleration of a car, we need to use the basic equations of motion. We'll break down the problem into two steps: (1) converting the given information into SI units and (2) using the equations of motion to find the initial velocity and deceleration.

Step 1: Convert the given information to SI units:
- The car is traveling at a speed of 5 m/s.
- The distance covered is 30 cm.

We need to convert the distance from centimeters to meters:
30 cm = 30/100 m = 0.3 m

So, the car travels a distance of 0.3 m.

Step 2: Use the equations of motion to find the initial velocity and deceleration.
The equations of motion we'll use are:

v = u + at
s = ut + (1/2)at^2

where:
v = final velocity
u = initial velocity
a = acceleration/deceleration
t = time taken
s = distance covered

In this case, we know:
v = 0 m/s (as the car comes to rest)
u = ? (initial velocity)
a = ? (deceleration)
t = 25 minutes = 25 * 60 seconds = 1500 seconds
s = 0.3 m

Using the second equation, we can rearrange it to find the initial velocity (u):

s = ut + (1/2)at^2
0.3 = u(1500) + (1/2) a (1500)^2

Since the final velocity (v) is 0 m/s, we can also use the first equation:

v = u + at
0 = u + a(1500)

Now we have a system of two equations with two unknowns (u and a).

To solve for u and a, we'll use simultaneous equations or substitution methods:

1) Using the first equation:

0 = u + a(1500) --> Equation (1)

2) Using the second equation:

0.3 = u(1500) + (1/2)a(1500)^2 --> Equation (2)

Now, we can solve this system of equations to find the values of u and a.

Let's solve it using substitution method:
From Equation (1), we can rearrange it as:

u = - a(1500) --> Equation (3)

Substituting Equation (3) into Equation (2):

0.3 = (-a(1500))(1500) + (1/2)a(1500)^2
0.3 = -2250a + 1125a
0.3 = -1125a
a = 0.3/(-1125)
a ≈ -0.000267 m/s^2

Now, substitute the value of a into Equation (3) to find u:

u = - a(1500)
u = -(-0.000267 m/s^2)(1500)
u = 0.4 m/s

Therefore, the initial velocity (u) is approximately 0.4 m/s, and the deceleration (a) is approximately -0.000267 m/s^2.