physics
posted by Anonymous .
A harmonic wave moving in the positive x direction has an amplitude of 3.1 cm, a speed of 37.0 cm/s, and a wavelength of 26.0 cm. Assume that the displacement is zero at x = 0 and t = 0.
Calculate the displacement (in cm) due to the wave at x = 0.0 cm, t = 2.0 s.

The wave equation for deisplacement (Y)is
Y = (3.1 cm)* sin [2 pi)(x/L  f*t)]
f is the frequency, which is
(37 cm/s)/(26 cm) = 1.423 Hz
Insert x = 0 and t = 2s to compute the answer. 
I'm still not getting the correct answer when I use the above formula. When I plugged in 0 for x and 2 for t, I simplified the equation to
Y= 3.1 * sin (2pi (2.846))
Y=3.1 * sin (17.88)
Y=3.1 * .307
Y=0.952 cm
What am I doing wrong? 
nevermind, I was stupid and didn't have my calculator in radians! Thank!