Monday

October 20, 2014

October 20, 2014

Posted by **Farah** on Monday, November 29, 2010 at 5:53am.

This is one of the questions in my practice test, I tried the basic equation of the trig function such as f(x)= sin(x) or f(x)=-sin(x) however in the fourth derivative they reach the same f(x) and the answer at the book says it is these and the cosine functions which will give the fifth derivative equal to the original equation. What is wrong with my working out?

- Math - derivative of sinusoidal (check) -
**Reiny**, Monday, November 29, 2010 at 8:51amy = sinx

y ' = cosx or dy/dx = cosx

y '' = -sinx

y ''' = -cosx

y '''' = sinx

y ''''' = cosx

so for y = sinx

the first derivative or dy/dx = cosx

and the fifth derivataive = cosx

so f(x) = sinx

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