posted by d on .
(OK. My answer made as much sense as your question. Did you forget to ask something here?) :-)
235/92U + 1/n ---> 90/38Sr + 3 1/n + ? in an easier format
The other heavy ion product of this must have an atomic weight of 236 -3 -90 = 143 and an atomic number of 92 -38 = 54
that would make the product 143/54Xe, but my table of nuclides (dated 1960) does not list this isotope. However, more modern tables do list it. I doubt if it is a major fission product of U-235.