235.over.92U + 1.over.n ---> 90.over.38Sr + 3 1.over.n + ??
Example:
235U
92
235/92U + 1/n ---> 90/38Sr + 3 1/n + ? in an easier format
Make the subscripts add to the same number on both side and make the superscripts add to the same number on both sides.
235/92U + 1/o n ==> 90/38Sr + 3 1/o n + X
So the subscripts on the left adds to 92+0 = 92.
On the right we have 38 + 0 + ?? = 92. That must 92-38 = 54. If I've interpreted your question properly, then we look on the periodic table and find element #54. That is Xe so we can place Xe in place of the unknown X. For the superscripts, we have
235 + 1 on the left.
On the right we have 90 + 3 + ?? = 236 so ?? must be 143.
I'm not sure what your 31.over n means but I think you will get the idea from this.
Thank you sir! Makes sense!
It is 3 and 1/n
That worked! Thank you so much!!
To solve this equation, we need to balance the equation by making sure that the number of atoms of each element is the same on both sides. Let's break down the equation step by step:
235.over.92U + 1.over.n ---> 90.over.38Sr + 3 1.over.n + ??
First, let's focus on the left side of the equation. We have Uranium-235 (235.over.92U) and an unknown element represented by 1.over.n.
On the right side, we have Strontium-90 (90.over.38Sr), another unknown element represented by 3 1.over.n, and an unknown element represented by ??.
To balance the equation, we need to apply the law of conservation of mass, which states that atoms are neither created nor destroyed in a chemical reaction.
Let's start by balancing the uranium atoms. On the left side, we have one atom of Uranium-235 (235.over.92U). To balance this, we need to have one atom of Uranium on the right side of the equation as well.
Now let's balance the number of neutrons (n). On the left side, we have one neutron represented by 1.over.n. On the right side, we have three neutrons represented by 3 1.over.n. Therefore, we need to have three neutrons on the left side as well.
Since we need one Uranium-235 atom and three neutrons, we can rewrite the equation as follows:
235.over.92U + 3 1.over.n ---> 90.over.38Sr + 3 1.over.n + ??
Now we can focus on balancing the strontium atoms. On the right side, we have one atom of Strontium-90 (90.over.38Sr). To balance this, we need to have one atom of Strontium on the left side as well.
Now let's balance the remaining unknown element represented by 1.over.n. On the right side, we have three of these unknown elements represented by 3 1.over.n. Therefore, we need to have three of these unknown elements on the left side as well.
The balanced equation is:
235.over.92U + 3 1.over.n ---> 90.over.38Sr + 3 1.over.n + ??
Now, since we've balanced the equation, we can see that the unknown element on the right side remains as it is. So the answer to this equation is ??.