Posted by Anonymous on Monday, November 29, 2010 at 12:32am.
The pOH is 10.
To convert pOH = 10 to OH^-, it is
pOH = -log(OH^-)
10 = -log(OH^-)
-10 = log(OH^-)
Take antilog of both sides.
1 x 10^-10 = OH^-
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