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May 19, 2013

Homework Help: chemistry

Posted by justin on Sunday, November 28, 2010 at 9:46pm.

You have 100.7 g of saccharin, a sugar substitute, and you want to prepare a pH = 5.80 solution. What volume of solution can be prepared? For saccharin (HC7H4NSO3), pKa = 11.70 (pKa = −log Ka).

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