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December 20, 2014

December 20, 2014

Posted by **dee** on Sunday, November 28, 2010 at 2:06pm.

- calculus -
**Reiny**, Sunday, November 28, 2010 at 3:07pmso distance = 4t^2 + c

when t=0, d=0, (hasn't gone anywhere yet)

so c=0

distance = 4t^2

so in 2 hours

distance = 4(2^2) = 16 m

(silly question, how can the speed keep increasing?

And it took 2 hours to go 16 m?

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