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calculus

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Suppose a scooter travels at a velocity of v(t)= 8t meters/hour. Then the TOTAL distance traveled by the scooter over the first 2 hours is?

  • calculus - ,

    so distance = 4t^2 + c
    when t=0, d=0, (hasn't gone anywhere yet)
    so c=0
    distance = 4t^2

    so in 2 hours
    distance = 4(2^2) = 16 m

    (silly question, how can the speed keep increasing?
    And it took 2 hours to go 16 m?

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