Complete and balance each of the following equations. If no reaction occurs, please enter NR in each answer box. (Type your answer using the format CO2 for CO2. Do not leave any box blank. Use the lowest possible coefficients.)
____Al4C3(s) + ___H2O ___Al(OH)3 + ___ _____
where ever there is a ___ something goes there. either a coefittiant or a molecule
http://en.wikipedia.org/wiki/Aluminium_carbide see reactions
I still don't get it, can u explain???
The equation is given balanced, in the link I gave, in reactions. Aluminum carbide and water yield methane and aluminum hydroxide. There is little to explain.
for the 3CH4. why is it $ and does C have to go before H??
I don't know what $ means in relation to this problem. If you meant to type 4, it is 4 because C is in column IV (or 14 depending upon the system your prof is using) which means it has an oxidation (valence) of 4. H is valence of 1 so the formula for methane is CH4. Must the C come first? Could we write as H4C. Written as H4C, CH4, or H2CH2, most will decipher that as CH4 which means methane. USUALLY, the more postive atom is placed first, which is why we write it CH4.
oh i got it:) thanks:)
To complete and balance the given equation, we need to identify the reactants and products and then balance the number of atoms on each side of the equation.
The reactants in the equation are Al4C3 (aluminum carbide) and H2O (water). The products are Al(OH)3 (aluminum hydroxide) and an unknown compound.
Let's balance the equation step-by-step:
Al4C3 + H2O → Al(OH)3 + _____
First, let's balance the aluminum (Al) atoms on both sides of the equation. There are 4 aluminum atoms in Al4C3 and 1 aluminum atom in Al(OH)3. To balance the aluminum atoms, we need to put a coefficient of 4 in front of Al(OH)3:
Al4C3 + H2O → 4Al(OH)3 + _____
Next, let's balance the hydrogen (H) and oxygen (O) atoms on both sides of the equation. There are 12 hydrogen atoms and 3 oxygen atoms in 4Al(OH)3. To balance the hydrogen and oxygen atoms, we need to put a coefficient of 6 in front of H2O:
Al4C3 + 6H2O → 4Al(OH)3 + _____
Now, let's balance the carbon (C) atom. There is 1 carbon atom in Al4C3. To balance the carbon atom, we need to put a coefficient of 1 in front of Al4C3:
Al4C3 + 6H2O → 4Al(OH)3 + _____
Finally, we have balanced all the atoms except for the unknown compound on the right side of the equation. Since we don't know the formula of the unknown compound, we represent it as a single molecule denoted by X:
Al4C3 + 6H2O → 4Al(OH)3 + X
Therefore, the balanced equation is:
Al4C3 + 6H2O → 4Al(OH)3 + X