Posted by **Eliza** on Sunday, November 28, 2010 at 11:09am.

1. a.) Find an equation for the line perpendicular to the tangent curve y=x^3 - 9x + 5 at the point (3,5)

[* for a. the answer that I obtained was

y-5 = -1/18 (x-3) ]

b.) What is the smallest slope on the curve? At what point on the curve does the curve have this slope?

c.) Find equations for the tangents to the curve at the points where the slope of the curve is 18.

- 12th Grade Calculus -
**Reiny**, Sunday, November 28, 2010 at 11:18am
a) correct

b) smallest slope ---> minimum slope

so set derivative of slope = 0

that is, the 2nd derivative = 0 and solve

c) set 3x^2 - 9 = 18 and solve

You will get two differenent x's, find the matching y's and do the usual thing to find the equation.

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