calculus4
posted by Ivan on .
2y^3y=7x^4 find dy/dx using differentiating implicity

6y^2 dy/dx  dy/dx = 0  4x^3 dx/dx
notice I wrote down dx/dx even though it has a value of 1, and i wouldn't have to include it.
Since you are differentiating with respect to x, whenever you work on a purely xterm, the dx/dx does not have to be written.
BUT, whenever you are differentiating a variable other than x, d(?)/dx has to be included.
so..
6y^2 dy/dx  dy/dx = 0  4x^3 dx/dx
dy/dx(6y^2  1) = 4x^3
dy/dx = 4x^3/(6y^2  1)