balance the formula
Cu(OH)2(s) + HNO3(aq) -> H2O(l) + fine the formula here(aq)
i did the H20 but i don't know the other formula i thought it was CuNO3 but that's wrong and idk what to do with the extra O
This is an acid-base reaction. It forms water + salt and the oxidation state (valence) of the Cu in Cu(OH)2 is +2; therefore, the formula for the nitrate of Cu is Cu(NO3)2. You tried to make an oxidation-reduction equation out of it and that won't work.
Cu(OH)2(s) + 2HNO3(aq) ==> 2H2O(l) + Cu(NO3)2
thanks
so for this equation:
HC2H3O2(aq) + Ca(OH)2(aq) -> H2O(l) + find the formula here
the last part would be CaOC2H3O2?
im a little confused. did the O fromt he H2O come from (OH)2?
To balance the chemical equation, first, let's break down the formula Cu(OH)2 to determine the number of atoms of each element involved:
Cu: 1 atom
O: 2 atoms (1 atom from OH group and 1 from the water molecule)
H: 2 atoms (from the OH group)
Now, let's examine the other side of the equation, which is HNO3(aq) -> H2O(l) + ?(aq):
H: 1 atom
N: 1 atom
O: 3 atoms
To balance the equation, we need to make sure that the number of atoms on both sides of the equation is equal.
To balance the hydrogen (H) atoms, we already have 2 H atoms on the left side. Therefore, we also need to have 2 H atoms on the right side.
For the nitrogen (N) atom, there is only 1 N atom on the left side. Therefore, we also need 1 N atom on the right side.
Now, let's balance the oxygen (O) atoms. There are 2 O atoms on the left side (1 from Cu(OH)2 and 1 from HNO3). On the right side, we have 1 O atom in H2O. This means that we have an extra O atom that needs to be balanced.
To balance this extra O atom, we can introduce another NO3 group. Each NO3 group contains 3 O atoms, so we will need to add another NO3 group to balance the equation.
Now, the balanced equation becomes:
Cu(OH)2(s) + 2HNO3(aq) -> H2O(l) + Cu(NO3)2(aq)
The formula Cu(NO3)2 represents copper nitrate, which is the product formed in the reaction.