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December 22, 2014

December 22, 2014

Posted by **mychelle** on Saturday, November 27, 2010 at 7:27pm.

- algebra 2 -
**Damon**, Saturday, November 27, 2010 at 8:21pma1 + a2 + a3 + a4 + a5 = 200

6 (a1 + a2) + a3 + a4 + a5 = 0

a1 = a1

a2 = a1 + m

a3 = a1 + 2m

a4 = a1 + 3m

a5 = a1 + 4m

so

5 a1 + 10m = 200

6(2 a1+ m) + 3 a1 + 9m = 0

a1 + 2 m = 40

15 a1 + 15 m = 0

m = -a1

a1 - 2a1 = 40

a1 = -40

m = 40

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