Posted by Linda on .
1. e^ln3  2lnx
2. 2(lnx)^2 + lnx  1 =0
3. d/dx (e^x . e^e^x)

calculus 
Damon,
1.
e^ln 3 = 3
so
3  ln x^2
2.
2z^2 +z1 = 0
(2z1)(z+1) = 0
z = 1/2 or 1
ln x = 1/2
e^ln x = x = e^.5 = 1.65
ln x = 1
e^1 = 1/e = .367
3.
do not understand notation