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March 1, 2015

March 1, 2015

Posted by **roni** on Saturday, November 27, 2010 at 6:14pm.

- physics please help -
**drwls**, Saturday, November 27, 2010 at 6:23pmThe initial kinetic energy of the bar, which is

(1/2) I wo^2 = (1/2)*M (L^2/3)*(vo/L)^2

= (1/6)*M vo^2

Must equal the increase in potential energy in the upside-down position, which is

M g L

since the center of mass raises by an amount L.

I is the moment of inertia of the rod about the pivot at the top.

M cancels out and you are left with

(1/6)vo^2 = g*L

Solve for vo

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