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A 25 mL sample of wine is found to have a concentration of acetic acid of 0.23 M. If this was titrated with a 0.16 M NaOH solution how many mL's of NaOH would be required?

  • Chemistry -

    How many moles of acetic acid do you have. M x L = ??
    How many moles NaOH will that require? It must be the same because the reaction between acetic acid and NaOH is 1:1.
    Then moles NaOH = M x L; you have moles NaOH and M NaOH, solve for L.
    For 1:1 reactions, the shorter mL x M = mL x M may be used.

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